Solved: The Polar Coordinates Of A Poni Are (-5,2pi/3).plo ~ Lifestyle Blog

Get an answer for 'Write the equation of the tangent function with a period of `2pi/5` and a vertical shift of 2 units up, and write the equation of the sine function with an amplitude of 1/7, aWrite any fractions like this: 5/2pi Here is the graph of a sin wave High B D A E Low I Given the function, y = 2sin(x + 3/4pi) + 5 Find: 1. Origin: horizontal, vertical e.g. -pi, 2: 2.So 12pi/5 = 2pi/5 = 2*(180)/5 = 75 degrees in Quadrant 1. Step-by-step explanation: 1.0 1 vote 1 vote Rate! Rate! Thanks Comments; Report Log in to add a comment Looking for something else? Looking for something else? Find more answers. New questions in Mathematics.So 12pi/5 = 2pi/5 = 2*(180)/5 = 75 degrees in Quadrant 1. aquialaska aquialaska Answer: Option A is correct .i.e., I. Step-by-step explanation: We have to tell in which quadrant Angle lies. First we simply the given angle, we know that . 2π represent one complete revolution.5. 2pi/3 + 2pi= 8pi/3; -4pi/3. Supplementary angles are two angles that add up to 180 degrees or pi radians so you must subtract every angle from pi. If it is not in QI, QII, you need to find the reference angle (the angle that is only in QI) then subtract. 1. pi - pi/6 = 5pi/6.

Solved: Write Any Fractions Like This: 5/2pi Here Is The G

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.Share a link to this widget: More. Embed this widget »Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

In what quadrant does the angle -8pi/5 terminate? I II III IV

Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.Vertical Lines . If you want a dashed vertical line for an asymptote, enter the equation (e.g., x = 4) with the Asymptote plot type.You can even enter multiple asymptotes at once. If you want a solid vertical line instead, enter the equation in the Implicit plot type.T = (2pi/1) * (5/2pi) T = 5... note how the '2pi' terms canceled out So the period is 5 This means that every 5 units on the x axis is when the graph repeats itself.color(blue)(0,pi,2pi,5.356,4.070)color(white)(88) ( 3 .d.p.) cosx-2sinx=1 Add 2sinx to both sides: cosx=1+2sinx Square both sides: cos^2x=(1+2sinx)^2 Subract (1+2sinx)^2 from both sides: cos^2x-(1+2sinx)^2=0 Using identity: color(red)(bbsin^2x+cos^2x=1) color(red)bb(cos^2x=1-sin^2x) 1-sin^2x-(1+2sinx)^2=0 Expand bracket: 1-sin^2x-(1+4sinx+4sin^2x)=0 1-sin^2x-1-4sinx-4sin^2x=0 -5sin^2x-4sinx=0Well . the perimeter of the semicircle is 2r+0.5(2pi*r) = 2r+pi*r. the perimeter of this particular semicircle is 14+7pi . Let the sides of the rectangle be x, x, x+1, and x+1

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